백준 2798번: 블랙잭

www.acmicpc.net/problem/2798

2798번: 블랙잭

 

구현 언어: 파이썬

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sum = 0
answer = 0
diff = 1000000
n, m = map(int, input().split())

cards = list(map(int, input().split()))

for i in range(0, n):
    for j in range(i+1, n):
        for z in range(j+1, n):
            sum = cards[i] + cards[j] + cards[z]
            if abs(sum - m) <= diff and sum <= m:
                answer = sum
                diff = abs(sum - m)

print(answer)

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시도 횟수: 4

 

구현 포인트:

브루트포스 ..

그리고 문제를 잘 읽자 ..